-50x^2+700x=0

Solution for -50x^2+700x=0 equation:

-50x^2+700x=0

a = -50; b = 700; c = 0;
Δ = b2-4ac
Δ = 7002-4·(-50)·0
Δ = 490000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{490000}=700$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(700)-700}{2*-50}=\frac{-1400}{-100}
=+14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(700)+700}{2*-50}=\frac{0}{-100}
=0
$